Quote:
Originally Posted by Jtomas801
Okay, so it sounds like its trying to find a rod that will support the load more than the bolt (5/8 or 3/4)
I am trying to learn a little bit of this, so if you see any thing wrong please let me know.
While searching through google, I found the equation for shear strength:
tensile strength pounds/in2 x cross sectional area.
In the case of a -10 an bolt with a tensile strength of 160,000 psi and a cross-sectional area of 0.306640625 in2 at the full diameter
160000 pounds/in2 x 0.306640625 in2 = 49062.5 pounds
If 49062.5 pounds is single shear, you double it to get 98125 double shear, right? That should be the amount of force to shear the bolt?
Thanks,
Jon
|
Your math looks correct! The weak link usually is the rod end not the bolt.